Implement Width Calculator
Optimal width from field size and workday.
Inputs
%
Results
Required width (ft)
23.8
Practical width (ft)24
Required EFC (ac/hr)11.9
Actual days at practical width6.9
HP needed for this width123
Max width for tractor (ft)38.9
Hp Adequate1
How to Use This Calculator
- Enter Total acres to cover and the Available days you have to cover them.
- Enter Hours per day and Operating speed (mph) for the planned operation.
- Set Field efficiency (%) to account for turns, overlap, and stops.
- Optionally enter Draft per ft width (lbs; disk 150-350, chisel 200-400) and Tractor engine HP to check HP adequacy, or set draft to 0 to skip that check.
- Read Required width (ft) and Practical width (ft) for the implement, plus Required EFC (ac/hr), Actual days at practical width, HP needed for this width, and Max width for tractor.
How the result changes with Available days
| Available days | Required width (ft) |
|---|---|
| 6.9 | 24.2 |
| 22 | 7.6 |
| 39 | 4.3 |
| 54 | 3.1 |
What each input means
- Total acres to cover
- Total field area that must be covered in the available time window.
- Available days
- Number of suitable field days available for the operation.
- Hours per day
- Expected working hours per field day.
- Operating speed (mph)
- Target field speed in miles per hour.
- Field efficiency (%)
- Field efficiency accounting for turns, overlap, and stops.
- Draft per ft width (lbs)
- Implement draft force per foot of width. Set 0 to skip HP check. Disk: 150-350, Chisel: 200-400.
- Tractor engine HP
- Available tractor engine horsepower for HP adequacy check.
What each result means
- Required width (ft)
- Minimum implement width needed to cover all acres in the time window.
- Practical width (ft)
- Required width rounded up to the next whole foot.
- Required EFC (ac/hr)
- Effective field capacity needed to meet the time constraint.
- Actual days at practical width
- Days needed at the practical (rounded) implement width.
- HP needed for this width
- Engine HP required to pull the implement at this width and speed.
- Max width for tractor (ft)
- Maximum implement width your tractor can handle at the given speed.
How this is calculated
Worked example, using the default values
- Identify Input Parameters4 parametersTotal acres to cover = 1000, Available days = 7, Hours per day = 12, Operating speed (mph) = 5.5 = 7 input(s) provided
- Calculate Required widthRequired width = (speedMph * efficiency) > 023.8 = 23.8
- Calculate Practical widthPractical width = ceil(requiredWidthFt)24 = 24
- Calculate Required EFC11.9 = 11.9
Engine last updated . Checked against 1 independently-derived test — how we verify calculators.
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