Quantum Entanglement Calculator
Calculate quantum entanglement measures including concurrence, von Neumann entropy, tangle, and Bell state fidelity.
About this calculator
This calculator quantifies how entangled a two-qubit quantum state is, starting from the four amplitudes you enter for the basis states |00⟩, |01⟩, |10⟩, and |11⟩. It first normalizes those amplitudes so their squared magnitudes sum to 1 (turning them into valid quantum probabilities), then computes concurrence — a standard entanglement measure that equals 0 for any separable state and 1 for a maximally entangled state like a Bell pair, using the formula C = 2|a₀₀a₁₁ − a₀₁a₁₀|. Squaring concurrence gives the tangle, and running concurrence through the entanglement-of-formation relation gives a second measure expressed in bits, both describing the same underlying entanglement from slightly different angles.
Separately, the calculator traces out the second qubit to get a reduced density matrix for the first, then computes its von Neumann entropy — a state with zero entropy is unentangled, while a maximally mixed reduced state (entropy of 1 bit) signals maximal entanglement, mirroring what concurrence already reported. The Bell state fidelity checks how closely your normalized state overlaps with the canonical |Φ+⟩ Bell state specifically, rather than entanglement in general, so a state can be strongly entangled yet score low on this particular fidelity if it's closer to a different Bell state. All of these measures assume you're describing a pure two-qubit state with real-valued amplitudes; genuinely complex amplitudes or mixed states (where the system is entangled with something outside the two qubits you're tracking) require a fuller density-matrix treatment this simplified calculator doesn't attempt.
Inputs
Results
Concurrence
1
Entanglement Entropy
1 bits
Tangle
1
How to Use This Calculator
- Enter the four two-qubit state amplitudes: |00⟩, |01⟩, |10⟩, and |11⟩. A Bell state (max entanglement) uses |00⟩ = |11⟩ = 1/√2 ≈ 0.707.
- The amplitudes don't need to be pre-normalized — the calculator automatically normalizes them, so the sum of squares doesn't need to equal 1 before you start.
- Read Concurrence (0–1): 0 means separable (unentangled), 1 means maximally entangled.
- Entanglement Entropy (bits) gives the von Neumann entropy: 0 for separable, 1 bit for a Bell state.
- Use Bell State Fidelity (%) to check how close your state is to a canonical Bell state.
How the result changes with |00⟩ Amplitude
| |00⟩ Amplitude | Concurrence | Entanglement Entropy | Tangle |
|---|---|---|---|
| 0.35 | 0.7993 | 0.721 bits | 0.6389 |
| 0.53 | 0.9599 | 0.9425 bits | 0.9214 |
| 1 | 0.9428 | 0.9182 bits | 0.8888 |
What each input means
- |00⟩ Amplitude
- Amplitude of the |00⟩ component
- |11⟩ Amplitude
- Amplitude of the |11⟩ component
- |01⟩ Amplitude
- Amplitude of the |01⟩ component
- |10⟩ Amplitude
- Amplitude of the |10⟩ component
How this is calculated
Formula
C = 2|a₀₀·a₁₁ - a₀₁·a₁₀|Worked example, using the default values
- Identify Input Parameters4 parameters|00⟩ Amplitude = 0.707, |11⟩ Amplitude = 0.707, |01⟩ Amplitude = 0, |10⟩ Amplitude = 0 = 4 input(s) provided
- Calculate ConcurrenceConcurrence1 = 1
- Calculate Entanglement EntropyEntanglement Entropy1 = 1
- Calculate TangleTangle1 = 1
- Calculate Entanglement of FormationEntanglement of Formation1 = 1
- Calculate Bell State FidelityBell State Fidelity100 = 100%
Engine last updated . Checked against 3 independently-derived tests — how we verify calculators. Built by Paul Gunder, a software engineer, not a licensed financial, medical, or legal professional.
Frequently Asked Questions
Why don't the entered amplitudes need to already satisfy the normalization condition?
Quantum states must have squared amplitudes summing to 1 to represent valid probabilities, but requiring you to compute that by hand before every attempt would make the calculator tedious to explore. Instead it divides all four amplitudes by their combined magnitude automatically, so you can enter any relative proportions and get a properly normalized state back.
Why do concurrence and entanglement entropy both measure the same thing?
They're two different mathematical approaches to quantifying entanglement in a two-qubit pure state, and for that specific case they're related but not identical — concurrence comes from the state's amplitudes directly, while entropy comes from the reduced density matrix of one qubit after tracing out the other. Both hit zero for separable states and their respective maximum for a Bell state, which is why they tend to move together.
Can a state have high concurrence but low Bell state fidelity?
Yes — concurrence measures entanglement in general, while Bell state fidelity specifically measures overlap with one particular Bell state, |Φ+⟩ = (|00⟩ + |11⟩)/√2. A maximally entangled state built instead from |01⟩ and |10⟩ would show concurrence of 1 but low fidelity to |Φ+⟩, since it's a different Bell state entirely.
What does zero entanglement entropy mean about the two qubits?
It means the two-qubit state is separable — it can be written as a simple product of an independent state for qubit A and an independent state for qubit B, with no quantum correlation between them. Measuring one qubit in that case tells you nothing about the other, unlike in an entangled state where the two outcomes become correlated.
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