Skip to main content
Calcimator

Fresnel Zone Calculator

Calculate Fresnel zone clearance radius for wireless link design. Includes earth curvature bulge and minimum antenna height.

About this calculator

A radio link needs more than a straight visual line of sight between antennas — it needs clearance around an elliptical volume called the first Fresnel zone, because RF energy that grazes an obstacle near this zone's edge can arrive out of phase with the direct signal and partially cancel it. This calculator computes that zone's radius at any point along the path using r = sqrt(n × wavelength × d1 × d2 / D), where d1 and d2 are the distances from each antenna to the obstacle location you specify (as a percentage along the path) and D is total path length; wavelength comes from the speed of light divided by frequency. It reports the first three Fresnel zones (n = 1, 2, 3) plus the maximum possible radius, which occurs at the path's midpoint.

The widely used design rule is that at least 60% of the first Fresnel zone must stay unobstructed for a link to perform close to free-space conditions, so the calculator highlights that 60% clearance figure directly. It also adds an Earth-curvature bulge — the extra height an obstacle effectively gains from the planet's curvature over distance, computed with the standard 4/3-Earth-radius approximation (k = 1.333) that accounts for how the atmosphere bends radio waves — and sums it with the 60% clearance to give a minimum antenna/tower height. The worst case is always the path midpoint (50% obstacle position), which is why that's the default; obstacles nearer either end require proportionally less clearance.

Inputs

MHz
km
%

Results

1st Fresnel Zone Radius

12.5 m

≈ 7 adult heights

60% Clearance (Min.)

7.5 m

≈ 4 adult heights

Min Clearance Height

7.87 m

≈ 5 adult heights

2nd Fresnel Zone Radius17.67 m
3rd Fresnel Zone Radius21.64 m
Max Radius (at Midpoint)12.5 m
Earth Curvature Bulge0.37 m
Wavelength0.1249 m
How to Use This Calculator
  1. Enter link frequency (MHz) and total link distance (km).
  2. Set the obstacle position along the path as a percentage of total distance (1% to 99%, with 50% as the worst-case midpoint).
  3. Review the 1st, 2nd, and 3rd Fresnel zone radii at the obstacle location.
  4. Ensure 60% of the 1st Fresnel zone is clear of obstacles for a clean line-of-sight link.
  5. Use the minimum clearance height, which adds the earth curvature bulge to the 60% clearance radius, to specify tower heights or choose alternate path routing.

How the result changes with Frequency

Frequency1st Fresnel Zone Radius60% Clearance (Min.)Min Clearance Height
1,20017.67 m10.6 m10.97 m
1,80014.43 m8.66 m9.03 m
3,60010.2 m6.12 m6.49 m
6,0007.9 m4.74 m5.11 m

What each input means

Frequency
Operating frequency of the wireless link in megahertz
Link Distance
Total distance between transmitter and receiver in kilometers
Obstacle Position Along Path
Position of obstacle as percentage of total path (50% = midpoint, worst case)

How this is calculated

Formula

r = √(n × λ × d₁ × d₂ / D)

Worked example, using the default values

  1. Identify Input Parameters
    Frequency = 2400, Link Distance = 5, Obstacle Position Along Path = 50 = 3 input(s) provided
  2. Calculate 1st Fresnel Zone Radius
    1st Fresnel Zone Radius
    12.5 = 12.5
  3. Calculate 60% Clearance
    60% Clearance = r
    7.5 = 7.5
  4. Calculate Min Clearance Height
    Min Clearance Height
    7.87 = 7.87
  5. Calculate 2nd Fresnel Zone Radius
    2nd Fresnel Zone Radius
    17.67 = 17.67
  6. Calculate 3rd Fresnel Zone Radius
    3rd Fresnel Zone Radius
    21.64 = 21.64

Engine last updated . Checked against 2 independently-derived tests — how we verify calculators. Built by Paul Gunder, a software engineer, not a licensed financial, medical, or legal professional.

Frequently Asked Questions

Why are the 2nd and 3rd Fresnel zones larger than the 1st at the same location?

All three use the same formula r = sqrt(n × wavelength × d1 × d2 / D), differing only in the zone number n (1, 2, or 3) multiplied inside the square root. Because it's inside a square root, the radius grows with sqrt(n) rather than linearly — the 2nd zone is about 1.41× the 1st zone's radius and the 3rd is about 1.73×, not simply double or triple.

Why does the calculator default the obstacle position to 50%?

The d1 × d2 product in the Fresnel radius formula is maximized when the obstacle sits exactly at the path midpoint (d1 = d2 = D/2), which is also where fresnelMax is computed directly as sqrt(wavelength × D / 4). Obstacles closer to either antenna produce a smaller Fresnel radius at that point, so the midpoint is the worst case for clearance planning and the sensible default to check first.

What is the Earth curvature bulge, and why use a 4/3 Earth radius?

It's the extra apparent height an obstacle gains partway along a long path purely because the Earth's surface curves away from a straight line between the antennas, computed as (d1 × d2) / (2 × Earth radius × 1.333). The 1.333 factor (4/3-Earth-radius approximation) doesn't come from the planet's actual curvature alone — it also accounts for how the atmosphere's refractive gradient bends radio waves slightly downward, effectively making the usable radio horizon appear as if Earth were about a third larger than it really is.

Why is only 60% of the first Fresnel zone required to be clear, not the whole radius?

Signal energy contributing to constructive interference is concentrated toward the center of the first Fresnel zone, and empirical link-planning experience shows that keeping the inner 60% of that radius free of obstructions preserves signal strength close to true free-space conditions. That's why the calculator reports clearance60 as a highlighted output alongside the full fresnel1 radius — it's the practical design threshold, not the theoretical zone boundary itself.

The questions that sit next to this one — chosen by subject, including calculators filed under a different category.

More in Technology & Computing.