RLC Resonance Calculator
Calculate the resonant frequency, Q factor, and bandwidth of a series RLC circuit. Visualize the impedance curve.
About this calculator
A series RLC circuit — resistor, inductor, and capacitor all in one loop — has a resonant frequency where the inductor's reactance and the capacitor's reactance cancel each other out exactly, leaving the circuit purely resistive. This calculator finds that frequency as f₀ = 1/(2π√(LC)), derived from setting the inductive and capacitive reactances equal, and reports the impedance at that point as simply R, since the reactive components cancel to zero. The Q factor, Q = (1/R)√(L/C), measures how sharply peaked the resonance is: a low-resistance circuit with a large inductance-to-capacitance ratio "rings" strongly and selects a narrow range of frequencies, while high resistance damps the response into a broad, shallow peak. Bandwidth (BW = f₀/Q) is the width of that resonance peak between the two "-3dB" points — the lower and upper frequencies where the circuit's response has dropped to about 70.7% of its peak value, computed here from a standard approximation involving Q and f₀.
The impedance-vs-frequency chart sweeps a logarithmic frequency range centered on resonance so you can see the characteristic V-shaped impedance dip (impedance is high away from resonance, where reactance dominates, and dips to its minimum, R, right at f₀). A frequent unit trap: capacitance and inductance values in real components are usually specified in microfarads/nanofarads and millihenries, so entering raw farads and henries without converting (for example, 100 nF should be typed as 0.0000001, not 100) will shift the computed resonant frequency by orders of magnitude. This model also assumes an ideal series topology — a parallel RLC circuit has a different, complementary relationship between R, bandwidth, and Q.
Inputs
Results
Resonant Frequency
5,032.92 Hz
Q Factor
31.62
Bandwidth
159.16 Hz
How to Use This Calculator
- Enter Resistance (R), Inductance (L), and Capacitance (C).
- Review Resonant Frequency (Hz), Q Factor, and Bandwidth (Hz).
- Use Impedance at Resonance (Ω) and Lower -3dB Frequency (Hz) to inform your decision.
- Use the chart to visualize the results and explore different scenarios by adjusting inputs.
How the result changes with Inductance (L)
| Inductance (L) | Resonant Frequency | Q Factor | Bandwidth |
|---|---|---|---|
| 0.01 | 7,117.63 Hz | 22.36 | 318.31 Hz |
| 0.01 | 5,811.52 Hz | 27.39 | 212.21 Hz |
| 0.02 | 4,109.36 Hz | 38.73 | 106.1 Hz |
| 0.03 | 3,183.1 Hz | 50 | 63.66 Hz |
What each input means
- Resistance (R)
- Series resistance in ohms. Lower R gives higher Q factor.
- Inductance (L)
- Inductance in henrys. 10 mH = 0.01 H.
- Capacitance (C)
- Capacitance in farads. 100 nF = 0.0000001 F.
How this is calculated
Worked example, using the default values
- Identify Input ParametersResistance (R) = 10, Inductance (L) = 0.01, Capacitance (C) = 1e-7 = 3 input(s) provided
- Calculate Resonant FrequencyResonant Frequency5032.921 = 5032.921
- Calculate Q FactorQ Factor31.623 = 31.623
- Calculate BandwidthBandwidth159.155 = 159.155
- Calculate Impedance at ResonanceImpedance at Resonance10 = 10
- Calculate Lower -3dB FrequencyLower -3dB Frequency4953.973 = 4953.973
Engine last updated . Checked against 1 independently-derived test — how we verify calculators. Built by Paul Gunder, a software engineer, not a licensed financial, medical, or legal professional.
Frequently Asked Questions
Why is impedance at resonance simply equal to R, with L and C not appearing at all?
At the resonant frequency f₀ = 1/(2π√(LC)), the inductive reactance (ωL) and capacitive reactance (1/ωC) are equal in magnitude and cancel in a series RLC circuit's total impedance calculation, leaving only the resistive component. That's why the engine sets impedanceAtResonance directly to the resistance value rather than computing it from a separate formula — the reactive parts have mathematically canceled to zero at that exact frequency.
How does the Q factor relate to how 'sharp' the resonance peak looks on the impedance chart?
Q is computed as (1/R)√(L/C), and since bandwidth is BW = f₀/Q, a higher Q means a narrower bandwidth relative to the resonant frequency — so a low-resistance circuit with a high inductance-to-capacitance ratio produces a tall, narrow V-shaped dip on the impedance-vs-frequency chart. Increasing resistance directly lowers Q, which widens the bandwidth and flattens that dip into a broader, shallower curve.
What do the lower and upper -3dB frequencies actually represent, and how are they calculated?
They mark the two frequencies bounding the bandwidth, where the circuit's response has fallen to about 70.7% of its peak — the engine derives them from a standard approximation, fLower/fUpper = f₀·(√(1 + 1/(4Q²)) ∓ 1/(2Q)), using only the resonant frequency and Q factor already computed. Their difference, fUpper − fLower, is what equals the bandwidth (f₀/Q) reported separately.
Would these same formulas apply if my inductor, capacitor, and resistor were wired in parallel instead of series?
No — this calculator explicitly models an ideal series RLC topology, where reactances cancel to leave R as the resonant impedance and a lower R gives a higher Q. A parallel RLC circuit has a complementary relationship instead: at resonance the parallel combination behaves as a high impedance, and it's a lower resistance that broadens (rather than sharpens) the response, so you can't reuse these series-derived Q and bandwidth relationships for a parallel design.
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