Manure Nutrient Value Calculator
N-P-K value from manure type and application rate.
Inputs
%
Results
Fertilizer value ($/acre)
$38.25
≈ 8 cups of coffee
Value per ton of manure ($)
$7.65
≈ 2 cups of coffee
Available N (lbs/acre)20
Available P₂O₅ (lbs/acre)17
Available K₂O (lbs/acre)36
Total N applied (lbs/acre)50
N value ($/acre)$11.00
P₂O₅ value ($/acre)$11.05
K₂O value ($/acre)$16.20
Total manure needed (tons)50
Total field value ($)$382.50
How to Use This Calculator
- Select Manure Type (Dairy, Beef Feedlot, Swine, Poultry Litter, or Horse) to load typical nutrient values.
- Enter the application rate in tons/acre or tons total.
- Review Nutrient Value ($/ton) and Total Value ($) — this is what you save on commercial fertilizer.
- Check N Availability (lbs/acre) separately from total N — only a fraction is plant-available in the first year.
- Compare P₂O₅ and K₂O applied per acre against your soil test recommendations to avoid over-application.
How the result changes with Application rate (tons/acre)
| Application rate (tons/acre) | Fertilizer value ($/acre) | Value per ton of manure ($) |
|---|---|---|
| 10 | $76.50 | $7.65 |
| 35 | $267.75 | $7.65 |
| 65 | $497.25 | $7.65 |
| 90 | $688.50 | $7.65 |
What each input means
- Manure type
- 1 = Dairy, 2 = Beef feedlot, 3 = Swine, 4 = Poultry litter, 5 = Horse.
- Application rate (tons/acre)
- Tons of manure applied per acre (as-is weight).
- Field size (acres)
- Total acres to receive manure.
- Excess moisture (%)
- Additional moisture above book values (dilutes nutrients). 0% = typical moisture.
- N price ($/lb)
- Commercial nitrogen price per pound.
- P₂O₅ price ($/lb)
- Commercial phosphate price per pound.
- K₂O price ($/lb)
- Commercial potash price per pound.
What each result means
- Fertilizer value ($/acre)
- Total nutrient replacement value per acre.
- Value per ton of manure ($)
- Economic value of each ton of manure.
- Available N (lbs/acre)
- Plant-available nitrogen in the first year.
- Available P₂O₅ (lbs/acre)
- Plant-available phosphate in the first year.
- Available K₂O (lbs/acre)
- Plant-available potash in the first year.
- Total N applied (lbs/acre)
- Total nitrogen applied (including unavailable fraction).
- N value ($/acre)
- Dollar value of nitrogen per acre.
- P₂O₅ value ($/acre)
- Dollar value of phosphate per acre.
- K₂O value ($/acre)
- Dollar value of potash per acre.
- Total manure needed (tons)
- Total tons of manure for the entire field.
- Total field value ($)
- Total nutrient replacement value for the whole field.
How this is calculated
Worked example, using the default values
- Identify Input Parameters4 parametersManure type = 1, Application rate (tons/acre) = 5, Field size (acres) = 10, Excess moisture (%) = 0 = 7 input(s) provided
- Calculate Fertilizer valueFertilizer value = nValue + pValue + kValue38.25 = $38.25
- Calculate Value per ton of manure7.65 = $7.65
- Calculate Available NAvailable N = totalNPerAcre * manure.nAvail20 = 20
- Calculate Available P₂O₅Available P₂O₅ = pPerTon * applicationRate * 0.8517 = 17
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